Help- me njxdhcdjewfrtthrtrh

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

sometimes it can be so they can fit in with a certain group, and others are just like that because of their personality.

the answer is c.) yes, [triangle]klp can be reflected across the line containing [line]kp and then translated so that p is mapped to m.

the reason is this:

looking at the triangles visually we can see they share the same features. using rigid transfromations we can reflect it over [line]kp then all we need to do is translate up.

answer: $53750

steps:

list the principal and interest after the n-th year:

n       principal   simple interest

1     12500     375

2     25000     750

3     37500     1125

4     50000     1500

sum: $50000     $3750

total at end of year 4: $53750