I need help please. Find 4 solutions of the equation (sin x)^2 = 1/4 for x between 0 and 360. Please show how you found it if not u will be reported.

Step-by-step explanation:

hope it helps.

x = 30, 150, 210, 330 degrees.

Step-by-step explanation:

(sin x)^2 = 1/4

sin x = +/- √1/4

sin x = +/- /2

In the first quadrant  x =  angle whose sine is 1/2 = 30 degrees.

There is also a solution in the other 3 quadrants.

In second quadrant  where sine = 1/2  , x = 180-30 = 150 degrees,

In 3rd and 4th where sine x = -1/2 the angles are 210 and 330 degrees.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.