Fig. A shows a paper cup in the shape of an inverted right circular cone. Its base radius is 4 cm and its slant height is 8.5 cm. (a) Find the capacity of the paper cup.

(b) The paper cup is cut along PQ to form the sector in Fig. B. Find
(i) the area of the sector,
(ii) the angle of the sector.

(a)
Height of the cup
=
=7.5 cm
The capacity of the cup
=
=126 cm³ (cor. to 3 sig. fig.)

(b)(i)
The area of the sector
=
=107 cm² (cor. to 3 sig. fig.)

Can you help me for (b)(ii)?​

9514 1404 393

  16π/17 radians ≈ 169.41°

Step-by-step explanation:

The arc length of the sector is the circumference of the cone:

  C = 2πr = 2π(4 cm) = 8π cm

The angle and arc length are related by ...

  s = rθ . . . . . θ in radians

  8π cm = (8.5 cm)θ

  θ = 8π/8.5 = 16π/17 . . . . radians

bii) The angle of the sector is 16π/17 radians ≈ 169.41°.

169° (3sf)

Step-by-step explanation:

the area of a circle multiplied by the angle over 360 gives you ans.

x/360 × π × r²=34π -> ur ans frm part i

x × π(8.5²)=12240π

x × 72.25=12240

x=169.41°

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

playboycarti! *

she tryna be crate.