So I have to factor polynomials by grouping The question: 2m^3-2m^2+3-3m

The answer is supposed to be: (2m^2-3)(m-1)

I do need steps

Thx

(2m^2-3)(m-1)

Step-by-step explanation:

2m^3-2m^2+3-3m

2m^3-2m^2-3m+3

2m^2(m-1)-3(m-1)

(2m^2-3)(m-1)

(2m^2-3)(m-1)

Step-by-step explanation:

2m^3-2m^2+3-3m

=(2m^3-2m^2)+(3-3m)

=2m^2(m-1)+3(1-m)

=(m-1)(2m^2-3)

=(2m^2-3)(m-1)

me

step-by-step explanation:

dont think so

step-by-step explanation: