Find the surface area of the net of a square pyramid. Formulas:

A=s2 A = bh A = 12h(b1+b2) A= lw A=12bh
SA = s2 +4(12bh)
SA = 2Lw + 2wh + 2Lh

choice:
180 cm2

144 cm 2

72 cm2

216 cm2

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

there is no question content here, but you for the free points! : d

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

the first one

step-by-step explanation:

just id the test.