There is a stack of 10 cards, each given a different number from 1 to 10. Suppose we select a card randomly from the stack, replace it, and then randomly select another card. What is the probability that the first card is an even number and the second card is less than 3?
Write your answer as a fraction in simplest form.

1/10.

Step-by-step explanation:

The probability of getting an even card out of 10 cards numbered 1 - 10 is 1/2. The even numbers available are 2, 4, 6, 8, and 10 while the odd ones available are 1, 3, 5, 7, and 9. So half the outcomes could come out even.

The probability the second card is less than two is 1/5 (2/10 simplified). Since there are 10 cards with numbers 1-10, only two cards will have numbers less than 3, 1 and 2.

To find the total probability, multiply the two. (1/2) * (1/5) = 1/10. There is a 1 out of 10 chance that the first card is even and the second card is less than 3.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !