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Mathematics, 28.04.2021 19:30 pedropaulofpedrosapp

The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n Equation 2: 3m = 4 + 4n Step 1:βˆ’3(m) = βˆ’3(8 + 2n) [Equation 1 is multiplied by βˆ’3.] 3m = 4 + 4n [Equation 2] Step 2:βˆ’3m = βˆ’24 βˆ’ 6n [Equation 1 in Step 1 is simplified.] 3m = 4 + 4n [Equation 2] Step 3: βˆ’3m + 3m = βˆ’24 βˆ’ 6n + 4n [Equations in Step 2 are added.] Step 4:0 = βˆ’24 βˆ’ 2n Step 5:n = βˆ’12 In which step did the student first make an error?

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The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n Equation 2: 3m =...
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