Which sequence has nth term 2n+5

a)7,21,35,
b)7,9,11,13
c)1,4,9,16

The answer is b.Look below for details.

Step-by-step explanation:

Question no 1. The sequence has the common difference of 14.

t1=7

t2=21

t3=35

We have

tn=a+(n-1)d

=7+(n-1)14

=7+14n-14

=14n-7(Its not our answer)

Lets try b.

The common difference is 2 in this sequence.

t1=7

t2=9

t3=11

t4=13

We have

tn=7+(n-1)2

=7+2n-2

=2n+5(Its is our answer.) Got it.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4