What is the solution to the function f(x)=x^2(x-2)^2 when x=2

According to the General Rule, the derivative of x 2 + 2 x for x is d d x [x 2] + d d x [2 x]. d d x [x 2] + d d x [2 x] Find the Derivative using the Rule of Power where d d x [x n] is n x n - 1 at n = 2. 2 x + d d x [2 x] Denote d d x [2 x]. ♥

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when x=2 then the answer is given by the function

f(x)=2^2(2-2)^2=4

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