A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different triangular cross sections are formed through the vertex and perpendicular to the base. What is the difference in the areas of the cross sections? Enter your answer in the box. m2
PLZ HELP

The answer is  30 m²

Step-by-step explanation:

step 1

find the area of the first cross section

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

step 2

find the area of the second cross section

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

step 3

find the difference in the areas of the cross sections

difference=60-30> 30 m²

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

difference=60-30> 30 m²

30 m²

Step-by-step explanation: hope this helps

could you reply to this with the question so i can ?

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted