ASAP someone please use the Pythagorean Theorem to solve for the missing side of these two right triangles.

9) x = 5

10) x = 4

Step-by-step explanation:

a^2 + b^2 = c^2

9) 6^2 + x^2 = 8^2

  - 36 + x^2 = 64

  -  36            - 36

           x^2 = 28

Square root them

Squareroot x^2 is x

Square root 28 is 5.29 round is 5

so x = 5

*Correct me if im wrong*

10) 3^2 + x^2 = 5^2

     9 + x^2 = 25

  -  9              - 9

             x^2= 16

Square root them

square root of x ^2 is x and square root of 16 is 4

so x = 4

she will most likely have 33  

step-by-step explanation: