Which technique(s) are appropriate to completely factor the expression?
A)
Factor as a difference of squares.
B)
Factor out the greatest common factor.
C)
Factor out the greatest common factor; then factor
the difference of squares.
D)
Factor out the greatest common factor; then factor
the perfect square trinomial

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

60 for the first and 130 for the second

step-by-step explanation:

113.42

i hope that is right.

step-by-step explanation: