Find the 14th term of the geometric sequence 9, 18, 36

9 × 2^(13)

Step-by-step explanation:

hello :

the nth term is :  An =A1 × r^(n-1)

a common ratio is : r  and  A1 the first term

in this exercice :   r= -3-(-7)36/18 = 18/9 =2         A1 = 9

when : n =14 you have the  14rd term  A14

A14 = 9 × 2^(14-1)  = 9 × 2^(13)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3