What is the value of the third quartile of the box plot shown? 39

39

25

25

20

20

19

19

hmmmn let me see it will take a min

Hello, I Am BrotherEye

Here is an Example On How To Solve Your Problem.

Step-by-step explanation:

Explanation:

29

,

33

,

36

,

37

,

39

,

40

,

41

The minimum is the lowest number in the data set.

Since it is listed from smallest to largest, we know that the minimum is

29

.

The median is the middle number. Cancel out

3

numbers from each side and we are left with the median:

29

,

33

,

36

,

37

,

39

,

40

,

41

Therefore, the median is

37

.

The first quartile (Q1) is the median of the lower half of data which lies at 25% of the data.

Let's look at the lower half of numbers:

29

,

33

,

36

The number in the middle is

33

, so that is the first quartile.

The third quartile (Q3) is the median of the upper half of data which lies at 75% of the data.

Let's look at the upper half of numbers:

39

,

40

,

41

The number in the middle is

40

, so that is the third quartile.

The maximum is the highest number in the data set; it is

41

.

So here's the five-number summary:

Minimum: 29

First quartile: 33

Median: 37

Third quartile: 40

Maximum: 41

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116