18 Find each item listed below for the data provided.
Test Scores: 50, 69, 70, 75, 75, 90, 85, 80, 70, 60, 100, 95, 90, 80, 85,50
(all answers should be rounded to the nearest tenth)
Mean:
Median:
Range:
IQR:

Mean: 78.2

Median: 80

Range: 50

IQR: 20

Calculator for mean, median, mode, range, & IQR: go to https://www.calculatorsoup.com/calculators/statistics/mean-median-mode.php

If you go to that link it will calculate that stuff, or if you just look up mean median and mode calculator

Step-by-step explanation:

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Have a fantastic day!!

the answer is d. (1.2, -4.7) on edgn

hope this !

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.