С In the figure below we have the 2 circles (CD) and (c) of the same center O and their radii are
R = 2cm and R2 = 4cm respectively. A straight line passing through O cuts (C) at F and A
and cuts (C) at B and E. The tangent to circle
(C:) at A cuts the circle (C) at C and D.
01) Show that (CD) is the perpendicular
bisector of [OB].
2) Determine the nature of the triangle OBC.
3) Show that the quadrilateral OCBD is a
thombus.
4) Let P be the midpoint of [CE].
a. Calculate OP and deduce that P belongs
to the circle (C1).
b. Show that D, O and P are collinear.
c. Show that (OP) is perpendicular to (CE)
and deduce that (CE) is tangent to (C1).
d. Show that (CO) is perpendicular to
(DE).
A
BU
0
D​

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).