Recall the differential equation for the instantaneous charge q (t) on the capacitor in an LRC series circuit is given by L d^2 q/dt^2 + R dq/dt + 1/C q = E(t). Use the Laplace transform to find q(t) when L = 1 henry, R = 20 ohms, C = 0.005 farads, E(t) = 50 volts, t > 0, q (0) = 0, and i (0) = 0. What is the current i(t)?

my answer got deleted but it's a

step-by-step explanation:

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

its kinda hard to answer this when we dont have all the information that we need.