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Mathematics, 20.04.2021 20:30 sparky1234

The work of a student to solve the equation 3(3y βˆ’ 8) = 10 + 3y is shown below: Step 1: 3(3y βˆ’ 8) = 10 + 3y
Step 2: 6y βˆ’ 5 = 10 + 3y
Step 3: 3y βˆ’ 5 = 10
Step 4: 3y = 15
Step 5: y = 5

In which step did the student first make an error and what is the correct step?

Step 2: 9y βˆ’ 24 = 10 + 3y
Step 2: 6y + 11 = 10 + 4y
Step 3: 6y βˆ’ 8 = 3(6 + y)
Step 3: 3(3y βˆ’ 8) = 7 + y

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Answers: 1

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