A classic physics problem states that if a projectile is shot vertically up into the
air with an initial velocity of 162 feet
per second from an initial height of 117
feet off the ground, then the height of
the projectile, h, in feet, t seconds after
it's shot is given by the equation:
h = – 16t2 + 162t + 117
Find the two points in time when the
object is 160 feet above the ground.
Round your answers to the nearest
hundredth of a second (two decimal
places)

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

i wish i could you, i have no idea how to answer this

step-by-step explanation: