Three times one number added to five times another number is 54. the second number is two less than the first. use a system of equations to find the numbers.
a.
7, 2
c.
8, 6
b.
8, 4
d.
10, 3

Let the first number be "x" and the second one "y"

Three times the first number is "3x" and five times the second number is "5y" and some of these is equalt to 54. So,

3x + 5y = 54

And if the second number is two less than the first, that means if we add 2 to the second number it will be equal to the first one, meaning ;

x = y+2

Now we have a system of equations. Let's solve.



From the second equation we have x's value. Will plug it in the first equation.



Now we have y's value. Let's plug it in one of the equations to find x.



So, (x, y) = (8, 6)

Answer is (8,6)

(1/x + 1)^2 + 6 (1/x + 1) +5

Ithink the answer is a