The relative frequency table shows the results of a survey in which parents were asked how much time their children spend playing outside and how much time they spend using electronics.

given that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics?

0.88

Step-by-step explanation:

Let A denotes the number of children spend at least 1 hour per day outside and B denote the number of children spend less than 1 hour per day on electronics .

From the given  relative frequency table , we have

The total number of children spend at least 1 hour per day outside = 16

Probability of a child spends at least 1 hour per day outside is given by :-

The total number of children spend less than 1 hour per day on electronics and spend at least 1 hour per day outside = 14

Probability of a child spends less than 1 hour per day on electronics and at least 1 hour per day outside is given by :-

The conditional probability of B , given that A is given by :-

Hence, the probability that the child spends less than 1 hour per day on electronics =0.88

so, converting firstly the mixed fractions to improper fractions and then "adding".