Line ab passes through a(-3, 0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to line ab ?

Since the line is parallel to AB, the two slopes are the same
        
                      slope of AB = m = (y₂-y₁)/(x₂-x₁)
                                     
                                           m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
                      The origin    P(0,0) 
                                       y=mx
                                       y= -x   Solution