Suppose ab=3x, bc=2y+16, ac=60, and b is the midpoint of ac. what are the values of x and y

Since we have two variable, then we need two equations:
first equation:
B lies on AC, therefore
AB+BC=AC
3x+2y+16=60
3x+2y=44 > equation I
second equation:
B is the midpoint of AC, therefore
AB=BC
3x=2y+16 > equation II
substitute wit II in I:
2y+16+2y=44
4y=28
y=7
substitute in II to gey x:
3x=2(7)+16
3x=30
x=10

The amount used= 13.04- 1.9 = 11.14