Ahigh school drama club is selling tickets for the spring production. one day the president sold 12 adult tickets and 5 child tickets for a total of $169. the next day the president sold 22 adult tickets and 10 child tickets for a total of $314. let a represent the cost of one adult ticket. let c represent the cost of one child ticket. which system of equations will solve for a and c?

12a + 5c = 169

22a + 10c = 314  

Step-by-step explanation:

A high school drama club is selling tickets for the spring production.

One day president sold 12 adult tickets and 5 child tickets for a total of $169.

Let cost of adult ticket is a and for child ticket c

Therefore, equation will be

12a + 5c = 169

Next day the president sold 22 adult tickets and 10 child tickets. so equation will be

22a + 10c = 314  

so these are system of equations

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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