Write an equation of the line that has a slope of 3 and contains the point (2,5) in point-slope form.

Point slope form is this equation
y - y1 = m(x-x1)
where m is the slope and (x1,y1) is the point the line goes through

The slope is 3, so let's replace m with 3
y - y1 = m(x-x1)
y - y1 = 3(x-x1)

The given point is (2,5) so let's replace x1 with 2 and y1 with 5
y - y1 = 3(x-x1)
y - y1 = 3(x-2)
y - 5 = 3(x-2)

y-5 = 3(x-2)

Ugh h h t t u i i vick u

With a continuous thought process.