If you are 1 million seconds old how old are you in years, using dimensional analasis

Simplify. −4x^2 (5x^4−3x^2+x−2) −20x^6−12x^4+8x^3−8x^2 −20x^6+12x^4−4x^3+8x^2 −20x^8+12x^4−4x^2+8x −20x^6+12x^4+4x^3−8x^2

The difference between two numbers is one. three times the larger number minus two times the smaller number is 9. what are the two numbers

Write the equation in logarithmic form 8^x=64