If y is 20% less than 90% of x and z is 25% more than 130% of y, then z is what percent of x?

This problem can be solved purely by analysis.

y is only 80% of 90% of x, therefore:

y = 0.80 * (0.90 * x)

y = 0.72 x                             ---> 1

z is 125% of 130% of y, therefore:

z = 1.25 * (1.30 * y)

z = 1.625 y                           ---> 2

Therefore combining 1 and 2:

z = 1.625 * (0.72 x)

z = 1.17 x

So z is 117% of x.

c: lkllmn.

hope it's you

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°