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which transformation causes the described change in the graph of the function y = cos x?
the transformation __ results in a horizontal shrink.
a. cos(x/5)
b. 9cos(x)
c. cos(3x)
d. cos(x+2)
the transformation __ results in a vertical stretch.
a. 1/3cos(x)
b. cos(x+4)
c. cos(-5x)
d. -5cos(x)
the transformation __ results in a horizontal stretch.
a. 2/7cos(x)
b. -3cos(x)
c. cos(7x)
d. cos(x/3)
the transformation __ results in a vertical shrink.
a. cos(x-2)
b. 2/3cos(x)
c. cos(4x)
d.2cos(x)

The answers are: A, D , C, B

Step-by-step explanation:

We have the function y = cosx and we need to check the changes of this function via various transformations.

1. Here, horizontal shrink is applied to y = cosx i.e. the value of 1/x has be to decreased or x>1. So, option C is correct.

2. Here, vertical stretch is applied i.e. overall value of function is increased. So, we can see that in option D, first vertical stretch is applied i.e. y = 5cosx and then reflection i.e. y = -5cosx.

3. Here, horizontal stretch is applied i.e. the value of 1/x has be to increased or 0<x<1. So, option D is correct.

4. Here, vertical shrink is applied i.e. the overall value of the function is decreased. So, option B is correct.

the answer is c

hope this !

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3