Which products result in a difference of squares? check all that apply. (x – y)(y – x) (6 – y)(6 – y) (3 + xz)(–3 + xz) (y2 – xy)(y2 + xy) (25x – 7y)(–7y + 25x) (64y2 + x2)(–x2 + 64y2)

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

answer: b

step-by-step explanation: