Luis has a change jar that contains only pennies and dimes. he has 74 coins which add up to a total of $4.61. how many of each type of coin does he have?

p +d = 74 coins

 rewrite as p =74-d

0.01p + 0.10d = 4.61

0.01(74-d) +0.10d = 4.61

0.74 - 0.01d +0.10d =4.61

0.74 +0.09d =4.61

0.09d = 3.87

d = 3.87/.09 = 43

p = 74-43 = 31

 43 dimes and 31 pennies

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.