Mathematics, 24.08.2019 03:00 JakkuZakku9436

How do you solve a problem like this
6x=5x+7

Answers: 2

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Answer from: telonfrippp5i9i5

6x=5x+7 subtract 5x from both sides x=7 hope this helps

Answer from: xXCoryxKenshinXx

You get all of the 'x's on one side of the equation, and everything else
on the other side.

I'll use your equation to demonstrate. Please watch closely:

   6x = 5x + 7

Subtract 5x from each side: x = 7 .

Oops. Ran out of steps. That's all this one needs.

' 7 ' is the 'solution' to this equation. That means: ' 7 ' is the number
that 'x' must be in order for the equation to be a true statement.
If 'x' is any other number but 7, the equation makes a statement
that's false.

Example: What if we make 'x' ten ? Then the equation says

6 (10) = 5 (10) + 7

60     = 50    + 7

   60 = 57    HONK ! Not true !    'x' can only be ' 7 ' .

Answer from: Quest

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

Answer from: Quest

answer:

given the linear inequality : $x-2y\geq -12$

add 2y to both sides we get;

$x-2y+2y\geq -12+2y$

simplify:

$x\geq -12+2y$

add 12 to both sides of an equation;

$x+12\geq -12+2y+12$

simplify:

$x+12\geq 2y$

divide both sides by 2 we get;

$\frac{x}{2} + 6 \geq y$

$y\leq \frac{x}{2} + 6$

the related equation for the inequality equation [1] is;

$y =\frac{x}{2} +6$

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

$y =\frac{0}{2} +6$

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

$0 =\frac{x}{2} +6$

subtract 6 from both sides we get

$0-6 =\frac{x}{2} +6-6$

$-6 =\frac{x}{2}$

multiply both sides by 2 we get;

$-6 \times 2=x$

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

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