Find two consequtive odd integers such that 4 times the first integer is 29 less than 7 times the second

Let the consecutive odd integers be x, x+2.

Given,

4x = 7(x + 2) -29

4x = 7x + 14 - 29

3x = 15

x = 5

Thus, the consecutive odd integers are 5 and 7.

Odd integers are 2 apart

so they are x and x+2

the first is x and the 2nd is x+2

4 times the first is 29 less than 7 times the 2nd

4x=-29+7(x+2)
solve
distribute
4x=-29+7x+14
4x=-15+7x
minus 7x both sides
-3x=-15
divide both sides by -3
x=5
x+2=7

the numbers are 5 and 7

He will need 2,898 pieces of paper