3x+2y+4z=12 x+y+2z=6 (x=0,y=4,z=1) determine if the given 2 lines intersect at the given point. explain your reasoning. -2x-4y+z=8 4x+2y=-5 (x=-2,y=0,z=3) same as up above

Equation 1: 3x + 2y + 4z = 12
Equation 2: x + y + 2z = 6

Substituting x = 0, y = 4 and z = 1 into equation 1 and equation 2 and if the answer equals to 12 and 6 then the two lines intersect at the given point

Equation 1 ⇒ 3(0) + 2(4) + 4(1) = 0 + 8 + 4 =12
Equation 2 ⇒ 0 + 4 + 2(1) = 4 + 2 = 6

We have the answer of 12 and 6, hence the two lines intersect at the given point


Equation 1: -2x - 4y + z = 8
Equation 2: 4x + 2y = -5

Given point: x = -2, y = 0, and z = 3

Equation 1 ⇒ -2(-2) - 4(0) + 3 = 4 - 0 +3 = 7
Equation 2 ⇒ 4(-2) + 2(0) = -8 + 0 = -8

The answers are not 8 and -5 hence the lines don't intersect at given point

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good