Solve for the zeros of the quadratic function f(x) = x + 5 – 2x2. 1. put the quadratic function in standard form. f(x) = –2x2 + x + 5 2. set the function equal to 0 to create a quadratic equation. –2x2 + x + 5 = 0 3. determine the values for a, b, and c. a = b = c = 4. analyze the discriminant. b2 – 4ac = the quadratic function will have .

Step-by-step explanation:

Put the quadratic function in standard form.

2. Set the function equal to 0 to create a quadratic equation

3. Determine the values for a, b, and c. a =2: b = -1:c = 5

4. Analyze the discriminant.

The quadratic function will have irrational real roots.

This is because discriminant is positive but not a perfect square

yes

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v