The probability that an individual is left-handed is 0.12. in a class of 39 students, what is the probability of finding five left-handers

0.1856

Step-by-step explanation:

Given that prob that an individual is left-handed is 0.12.

n = sample size = no of students = 39

q = 1-p = 0.88

Let X be the no of students who are left handed.

X is binomial since each student is independent of the other and there are only two outcomes

X:Bin(39, 0.12)

Probability of finding five left-handers

=P(X=5)

= 39C5 (0.12)^5 (0.88)^34

=0.1856

Answer is 0.1856

the answer is simply just 6n add the two together as they have an n

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x