3sets of traffic lights on route. there is a fifty fifty chance of lights being te or green. what are chances of getting 3 consecutive green lights

1/6

Step-by-step explanation:

Let probability of green be G and The be T

There are 6 possible outcome

GGG

GGT

GTT

TTT

TGT

BGG

Probability of it being green

=50/100= 1/2

Probability of 3 consecutive G

= GGG= 1/2 *1/2 *1/2

=1/6

so then what are you asking?

step-by-step explanation:

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!