Car salesman sells cars with prices ranging from $5,000 to $45,000. the histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years. the salesman has observed that many students are looking for cars that cost less than $5,000. if he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected? athe mean will shift to the right. b the mean and the median will be the same. c the median will shift to the right. d the mean will shift to the left.

This problem would be easier to understand if given the graph which you forgot to attach with the problem. However I dug up on other sources and I think I have found the right graph to go along with this (see attached pic).

We can see from the graph that the data of car price against number of cars sold over 10 years is perfectly normally distributed. That is, it forms a symmetrical bell curve. Since the data is perfectly normally distributed, therefore the mean and median is situated at the middle.

Now if the car salesman also decides to sell 200 cars costing less than $5,000, then we would see a blue bar to the left of the 5,000 interval. Hence our curve will no longer be symmetrical. Since the adjustment made is on the left, then obviously the mean and median would shift to the left. However they would no longer be the same since they are calculated differently so in an assymetrical curve, they would be different.

D The mean will shift to the left.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

multiply length by height. multiply the length by the height, and then double the product. work out 10 x 10 results = 100 square inches, then work out 100 x 2 = 200. the answer is 200 square inches.

step-by-step explanation: