The 200-meter race times at a state track meet are normally distributed with a mean of 13.56 seconds and a standard deviation of 2.24 seconds. using the standard normal probabilities table, what is the approximate probability that a runner chosen at random will have a 200-meter time less than 13.5 seconds?

P(X< 13.5) = 0.834

Step-by-step explanation:

Given data:

mean of race time is

standard deviation is

we know that z is given as

where x is 13.5 in given problem

so probability of having runner time less than 13.5

P(X< 13.5) = P(z< -0.026)

P(X< 13.5) = P(z>(1 -0.026))

P(X< 13.5) = P(z > 0.974)

from standard z table , for z = 0.974 we have 0.834

P(X< 13.5) = 0.834

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !