Acable capable of pulling 4,500 n snapped while trying to drag a 20,000 n compressor across the street. what is the coefficient of static friction for this scenario?
note: the 4500 n cable is used as fs and is calculated the same as fk

0.225

> 0.225

4,500 n

> 4,500 n

4.44

> 4.44

a

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

answer is b

step-by-step explanation: