The length of a rectangle is 2 cm longer than its width. if the perimeter of the rectangle is 40 cm , find its area.

width = w

 length = w +2

perimeter = 2L + 2w

40 = 2(w+2) + 2w

40 = 2w+4 +2w

40 = 4w+4

36=4w

w=36/4 = 9

with = 9

length = 9+2 = 11

 area = l x w = 9*11 = 99 square cm

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value