Astudent drives 4.8-km trip to school and averages a speed of 22.6 m/s. on the return trip home, the student travels with an average speed of 16.8 m/s over the same distance. what is the average speed (in m/s) of the student for the two-way trip? (be careful.)

19.3 m/s

Step-by-step explanation:

Given : Distance between home and school = 4.8 km= 4800 meters

(∵ 1 km= 1000 meters)

Formula to calculate time :

From home to school ,

Distance= 4800 m

Speed = 22.6 m/s.

From school to home ,

Distance= 4800 m

Speed = 16.8 m/s.

Now, the average speed (in m/s) of the student for the two-way trip is given by :-

Hence, the average speed (in m/s) of the student for the two-way trip= 19.3 m/s .

im pretty sure its

(8,15)

step-by-step explanation: