The function h(t) = −16t2 + 64t + 12 shows the height h(t), in feet, of a baseball after t seconds. a second baseball moves in the air along a path represented by g(t) = 10 + 10.4t, where g(t) is the height, in feet, of the object from the ground at time t seconds.
part a: create a table using integers 1 through 4 for the 2 functions. between what 2 seconds is the solution to h(t) = g(t) located? how do you know? (6 points)
part b: explain what the solution from part a means in the context of the problem. (4 points)

Two functions are:

H(t) = -16t² + 64t + 12

g(t) = 10 + 10.4t

Part A:

to find: table showing value of h(t) and g(t) for t = 1 , 2 , 3 , 4

Table is attached.

The solution to H(t) = g(t) is located between 3 and 4 seconds. because between 3 & 4 value of H(t) goes from 60 to 12 and value g(t) goes from 41.2 to 51.6   only in these intervals we can get equal values of H(t) and g(t).

Part B:

Solution for t,

H(t) = g(t)

- 16t² + 64t + 12 = 10 + 10.4t

- 16t² + 53.6t + 2 = 0

We find value of t using quadratic formula,

we get,

t = 3.39 seconds other value is neglected because of negative value.

This shows that at time 3.39 seconds both balls are at same height.

the answer is 37

step-by-step explanation: