What is the area between the circles of x^2+y^2=36 and (x-1)^2+(y-2)^2=4

In order to solve this problem, the primary equation to be used in this problem is the formula of the area of the circle which is A = pi r^2 where pi is a constant and r is the radius of the circle. The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius of the circle. In this case, 

1) first circle
x^2 + y^2 = 36
that is (h,k) is at (0,0) and r = 6
2) second circle
(x-1)^2+(y-2)^2=4
that is (h,k) is at (1,2) and r =2

The area of the first circle is A1 = pi *6^2 = 36pi while A2 = pi* 2^2 = 4 pi
The difference of the two is equal to 32 pi or equal specifically to 100.48 units^2

10120202020000000304040404

2936688fdyvdyfhhtdhjwkkviyuw