Apolynomial function has a root of –6 with multiplicity 3 and a root of 2 with multiplicity 4. if the function has a negative leading coefficient and is of odd degree, which could be the graph of the function?

step-by-step explanation:

if a polynomial function is having a root as (-6) with multiplicity of 3 and another root of 2 with multiplicity of 4 then (x + 6) and (x -2) are the two zero factors.

roots   (-6) multiplicity 3

            (2) multiplicity 4

since multiplicity of (-6) is odd then graph will cross x axis at x = -6.

now the function has a root x = 2 with multiplicity even therefore graph will touch x axis at x = 2 and further bounces up.

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5