Given a positive integer n, assign true to is_prime if n has no factors other than 1 and itself. (remember, m is a factor of n if m divides n evenly.)

Below is the solution of assign true to is_prime if n has no factors other than 1 and itself.

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Given a positive integer n, assign true to is_prime if n has no factors other than 1 and itself. And remember, m is a factor of n if m divides n evenly. So:

if n == 2:

is_prime = True

elif n % 2 == 0:

is_prime = False

else:

is_prime = True

for m in range (3, int(n**0.5)+1, 2):

if n % m == 0:

is_prime = False

Grade:  9

Subject:  mathematics

Chapter:  python

Keywords:  python, integer, factors, python IDLE, is_prime

no this is a nonlinear negative