Find the polynomial f(x) that has the roots of -2, 5 of multiplicity 2. explain how you would verify the zeros of f(x).

If -2 is a root of f, then (x-(-2))=(x+2) is a factor of f

similarly, if 5 is a root of f, then (x-5) is a factor of f(x).

These roots have multiplicity 2 means that there are 2 of each,

so f(x) is written as (x+2)(x+2)(x-5)(x-5)



[the most general form is f(x)= c*(x+2)^{2} (x-5)^{2}*P(x), where c is a constant and P(x) another polynomial]

To show that -2 and 5 are zeros of f, we must prove that f(-2)=0 and f(5)=0,

Using the function we wrote:



similarly:

There is no graph but what i can say is that 1 is the slope and that -2 is the y- intercept