Find an equation for the line with the given properties, express the equation in slope-intercept form. p=(-3,5) and q=(-2,3)

(-3,5)(-2,3)
slope = (3 - 5) / (-2 - (-3) = -2 / 1 = -2

y = mx + b
slope(m) = -2
use either of ur points...(-2,3)x = -2 and y = 3
now we sub and find b, the y int
3 = -2(-2) + b
3 = 4 + b
3 - 4 = b
-1 = b

so ur equation is : y = -2x - 1 <==