If f(–2) = 0, what are all the factors of the function f(x)=x^3 -2x^2-68x-120 use the remainder theorem. a) (x + 2)(x + 60) b) (x – 2)(x – 60) c) (x – 10)(x + 2)(x + 6) d) (x + 10)(x – 2)(x – 6)

solution:

we have been asked to use remainder theorem to find the factors of

we have been given that f(–2) = 0, it mean that (x+2) is one of the factor of the given function.

hence the factors are (x+-+6)

hence the correct option is (x – 10)(x + 2)(x + 6)

answer:

c is the correct answer

the correct answer to your question is a. 4^4

good luck my friend!

hope this !

maybe if i you could me by giving me brainliest?

! < 3

have a splendid day < 3 : )

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.