Suppose sn is defined as 2 + 22 + 23 + . . + 2n . what is the next step in your proof of sn = 2(2n - 1), after you verify that sn is valid for n = 1?
a. show that sn is valid for n = k + 2.
b. assume that sn is valid for n = k .
c. verify that sn is valid for n = 1.
d. show that sn is valid for n = k.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions