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Line bc has an equation of a line y = 2x + 3, and line ef has an equation of a line y = negative one over 2 x + 4. these two equations represent
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Given: klmn is a parallelogram m? n=3m? k, lf ? kn , ld ? nm kf=2 cm, fn=4 cm find: lf, ld
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Line bc has an equation of a line y = 2x + 3, and line ef has an equation of a line y = negative one...
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